return statement in call block returns from surrounding method instead of returning from call block.
Following code snippet describes it with example.
def function1(&block)
callback_result = yield('value1', 'value2')
puts "call block returned: #{callback_result}"
end
def function2()
function1() do |param1, param2|
puts "block implementation of function2 with param1 => #{param1} & param2 => #{param2}"
return "#{param1} changed. #{param2} changed."
end
puts "next line after calling function1"
return "function2 returned"
end
def function3()
function1() do |param1, param2|
puts "block implementation of function3 with param1 => #{param1} & param2 => #{param2}"
"#{param1} changed. #{param2} changed."
end
puts "next line after calling function1"
return "function3 returned"
end
output of function2() is
block implementation of function2 with param1 => value1 & param2 => value2
"value1 changed. value2 changed."
Output of function3() is
block implementation of function3 with param1 => value1 & param2 => value2
call block returned: value1 changed. value2 changed.
next line after calling function1
"function3 returned"
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1 comment:
Brother,
I am working as Senior Engineer in an ISP and responsible for developing and maintaining our company website and internal web applications and some other jobs. Currently I have an assignment to learn Ruby on Rails for managing a web application based on RoR. So I would like to join the seminar you arranged with bdjobs.com on the 23rd January of 2010. As a newbie of RoR I want to have some idea to get started. My interests are:
1. Installing Rails in different OS (Linux & Windows)
2. Choosing the best platform/OS to develop web application using Rails. (As I work in windows platform)
3. And some other things
I sent a mail to rorseminar@bdjobs.com to register me to the seminar though I haven't yet received any reply.
Thank you.
Regards,
Mohammad Moinul Hossain
E-mail: emoinul@gmail.com
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